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=125016H^2
We move all terms to the left:
-(125016H^2)=0
a = -125016; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-125016)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$H=\frac{-b}{2a}=\frac{0}{-250032}=0$
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